Jet Copies

Assignment #1: airlift lightning Copies Case Problem 1. How was the data compel in each instalment of the model? According to the schooling that was given for leafy ve dieable Copies, I was able to calculate intellect on ergodic variables how untold it would have cost JET Copies if the copy machine had disordered down. The first thing that I postulate to calculate was the geezerhood it would take to revivify the copier. infra you can have the contrive that was given in the lesson news report for the amount of long 4th dimension the copier would take to repair: 0 < ergodic measure < 0.2, why it takes 1 day 0.2 < random value < 0.65, and then it takes 2 days 0.65 < random value < 0.90, then it takes 3 days 0.9 < random value < 1, then it takes 4 days nigh I looked at the interval of how many a(prenominal) time it would partition in the midst of 0 and 6 weeks with the probability increasing as time goes on (Taylor, B. W. 2011). I substance abused the probability statistical dissemination formula down the stairs to generate that function: F(x) = x/18, for 0?x?6 where X= time between breakdowns When I substituted the information that was given in the text into this formula you get: F(x) = x²/36 for 0?x?6 Or X= 6?r1 coterminous I needed to project the amount of bemused gross JET Copies would escape if the copier was down all(prenominal) six weeks and the copier took 0-4 days to fix.

Using the uniform distribution between 2000-8000 according to the surmount data below for scattered revenue you can see the amount of revenue scattered in a true length of days. In accretion to compute the amount of muzzy revenue would be to use the R3 calculations times the repair time calculations (y). P(x)| Cumulative| Repair fourth dimension| 0.2| 0| 1| 0.45| 0.2| 2| 0.25| 0.65| 3| 0.1| 0.9| 4| 1| 1|  | segmentation (year)| R1| sentence Between Breaking, (x)| Cumulative Time| R2| Repair Time (y)| R3| mixed-up Revenue Cost ($)| 1| 0.1808| 1.70| 1.70| 0.3553 | 2| 6321| $ 12,642 | 2| 0.4281| 2.62| 4.32| 0.1553 | 1| 6338| $ 6,338...If you want to get a full essay, order it on our website: Orderessay

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